Circles in the Coordinate Plane
TipLearning Objectives
- Identify center and radius from circle equations.
- Interpret geometric features of circles on the coordinate plane.
- Convert between standard and expanded forms.
Key Ideas
Standard Form
\[ (x-h)^2 + (y-k)^2 = r^2 \]
- Center \((h,k)\)
- Radius \(r\)
Expanded Form
Complete the square to convert to standard form.

Common Problem Types
Identifying Center and Radius
From \((x-h)^2+(y-k)^2=r^2\).
Converting Expanded → Standard
Complete the square for \(x\)-terms and \(y\)-terms.
Check Whether a Point Lies on Circle
Plug into equation.
Circle–Line Intersection (Basic SAT)
Substitution to check if point is inside, on, or outside.
Strategies
- Move constants to one side before completing square.
- Group \(x\)-terms and \(y\)-terms together.
- Square half the coefficient.
Worked Examples
Example 1
Find center and radius:
\((x-3)^2 + (y+2)^2 = 49\)
Center = \((3,-2)\)
Radius = \(7\)
Example 2
Convert to standard:
\(x^2 + y^2 - 4x + 6y + 9 = 0\)
Group terms:
\((x^2 - 4x) + (y^2 + 6y) = -9\)
Complete squares:
\((x-2)^2 - 4 + (y+3)^2 - 9 = -9\)
Move constants:
\((x-2)^2 + (y+3)^2 = 4\)
Radius \(=2\).
WarningCommon Mistakes
- Forgetting to add square-completion constants to both sides.
- Incorrectly identifying signs of center.
- Using radius instead of radius-squared.
Practice Problems
- Find center & radius: \((x+1)^2+(y-5)^2=64\).
- Convert: \(x^2 + y^2 + 8x - 4y - 5 = 0.\)
- Does (3,2) lie on \((x-3)^2+(y-2)^2=0\)?
TipStep-by-Step Solutions
- Center = \((-1,5)\), radius = 8.
- Standard: \((x+4)^2 + (y-2)^2 = 25.\)
- Substitution gives 0 → yes, it is the center (degenerate circle).
Summary
- Standard form reveals center and radius.
- Complete square for conversions.
- Use substitution to test points.
TipQuick Tips
- Flip the sign inside parentheses to get the center.
- Radius is \(\sqrt{r^2}\), not \(r^2\).