Trig Ratios (SOH–CAH–TOA)
TipLearning Objectives
- Define the sine, cosine, and tangent ratios in right triangles.
- Identify opposite, adjacent, and hypotenuse relative to an acute angle.
- Evaluate trig ratios for common right triangles.
- Apply SOH–CAH–TOA to solve for missing sides or angles.
Key Ideas
In a right triangle, for an acute angle \(\theta\):
- Sine: \[ \sin \theta = \frac{\text{opposite}}{\text{hypotenuse}} \]
- Cosine: \[ \cos \theta = \frac{\text{adjacent}}{\text{hypotenuse}} \]
- Tangent: \[ \tan \theta = \frac{\text{opposite}}{\text{adjacent}} \]
“SOH–CAH–TOA” is the memory aid.

Common Problem Types
Identifying Opp/Adj/Hyp
Given a marked angle, identify each side relative to that angle.
Evaluating Trig Ratios
Example: \(\sin\theta = 3/5\) in a triangle with opposite 3, hypotenuse 5.
Solving for a Missing Side
Use \(\sin\), \(\cos\), or \(\tan\) and multiply/divide accordingly.
Finding an Angle from a Ratio
Use inverse trig (e.g., \(\theta = \sin^{-1}(0.6)\)) when needed.
Using Special Triangles
Use \(30^\circ\)–\(60^\circ\)–\(90^\circ\) and \(45^\circ\)–\(45^\circ\)–\(90^\circ\) ratios when applicable.
Strategies
- Always anchor the sides relative to the reference angle.
- Use the ratio that involves the given side and the unknown side.
- Draw a quick sketch if the triangle isn’t shown.
- Leave answers in exact form unless decimals are required.
Worked Examples
Example 1
In a right triangle, \(\theta\) has opposite side 8 and hypotenuse 17.
\[
\sin\theta = \frac{8}{17}
\]
Example 2
Find \(x\) if \(\cos 30^\circ = \frac{x}{10}\). \[ x = 10\cos 30^\circ = 10\left(\frac{\sqrt3}{2}\right)=5\sqrt3 \]
WarningCommon Mistakes
- Mixing up opposite and adjacent.
- Using the wrong reference angle.
- Forgetting that trig ratios apply only in right triangles (for now).
- Rounding too early.
Practice Problems
- If \(\sin\theta = 4/5\), what is the opposite/hypotenuse ratio?
- In a right triangle, \(\tan\theta = 3/4\) and adjacent = 12. Find opposite.
- Solve: \(\cos\theta = 0.6\).
- A ladder leans against a wall with angle \(60^\circ\) to the ground. Height if ladder is 12 ft?
TipStep-by-Step Solutions
- Opp = 4, Hyp = 5
- \(\tan\theta = \frac{\text{opp}}{12}=3/4\) → opp = 9
- \(\theta = \cos^{-1}(0.6)\)
- \(12\sin60^\circ = 12(\sqrt3/2)=6\sqrt3\)
Summary
- Use SOH–CAH–TOA to find missing sides or angles.
- Opp/Adj depend on the chosen angle.
- Special triangles help produce exact values.
TipQuick Tips
- Identify the reference angle first.
- Use the ratio that uses the known and unknown sides.
- Leave radicals in simplified exact form when possible.