Vectors
By the end of this lesson, you’ll be able to:
- Represent vectors graphically and in component form.
- Add, subtract, and scale vectors using components.
- Compute magnitude and direction.
- Apply vectors to displacement, velocity, and force problems.
Key Ideas
A vector has:
- magnitude (length)
- direction
Common representations:
- Arrow in the plane
- Component form:
\[ \langle a,\, b \rangle \] - As difference of two points:
\[ \overrightarrow{AB} = \langle x_B - x_A,\; y_B - y_A \rangle \]
Magnitude of vector \(\langle a, b \rangle\): \[ \|\langle a, b \rangle\| = \sqrt{a^2 + b^2} \]
Direction angle \(\theta\) (from positive x-axis): \[ \tan \theta = \frac{b}{a} \]
Operations:
Addition:
\[ \langle a,b \rangle + \langle c,d \rangle = \langle a+c,\, b+d \rangle \]Subtraction:
\[ \langle a,b \rangle - \langle c,d \rangle = \langle a-c,\, b-d \rangle \]Scalar multiplication:
\[ k\langle a,b \rangle = \langle ka,\, kb \rangle \]
Common Problem Types
Finding a Vector From Two Points
Use the difference of coordinates.
Example:
\(A(1,2)\), \(B(6,5)\)
\[
\overrightarrow{AB} = \langle 6-1,\; 5-2 \rangle = \langle 5,3 \rangle
\]
Magnitude of a Vector
Use the distance formula.
Example:
\[
\|\langle 4, -3 \rangle\| = 5
\]
Adding or Subtracting Vectors
Add or subtract components.
Example:
\[
\langle 2,5 \rangle + \langle -1,4 \rangle = \langle 1,9 \rangle
\]
Scalar Multiples
Multiply each component.
Example:
\[
3\langle 2,-1 \rangle = \langle 6,-3 \rangle
\]
Displacement / Velocity Applications
Vectors represent movement in the plane.
Example:
Walk \(\langle 3,4 \rangle\) blocks, then \(\langle -1,2 \rangle\):
Total \(= \langle 2,6 \rangle\).
Strategies
- Draw arrows to visualize direction.
- Combine components carefully — avoid mixing x and y.
- Scalar multiplication stretches or shrinks magnitude.
- Check quadrant when finding direction angle.
- Magnitude is always nonnegative.
Worked Examples
Example 1 — Find magnitude and direction
Given \(\vec{v} = \langle 6, 8 \rangle\):
Magnitude: \[ \sqrt{6^2 + 8^2} = 10 \]
Direction: \[ \tan \theta = \frac{8}{6} \Rightarrow \theta \approx 53.13^\circ \]
Example 2 — Add vectors
Compute: \[ \langle 4, -1 \rangle + \langle -2, 6 \rangle \]
Solution: \[ \langle 2, 5 \rangle \]
Example 3 — Vector between points
Find \(\overrightarrow{PQ}\) for \(P(-3,1)\) and \(Q(5,4)\):
\[ \langle 5 - (-3),\, 4 - 1 \rangle = \langle 8, 3 \rangle \]
Example 4 — Displacement
A plane travels east \(300\) miles and north \(400\) miles.
Total displacement vector: \[ \langle 300, 400 \rangle \]
Magnitude: \[ \sqrt{300^2 + 400^2} = 500 \text{ miles} \]
Direction: \[ \tan \theta = \frac{400}{300} \]
- Mixing up direction angle with slope.
- Forgetting to square components when finding magnitude.
- Switching the order in \(\overrightarrow{AB}\) (should be \(B-A\)).
- Treating vectors as points instead of directed segments.
- Sign errors when adding/subtracting.
Practice Problems
- Find the magnitude: \(\langle -3, 4 \rangle\).
- Add: \(\langle 1,2 \rangle + \langle 5,-7 \rangle\).
- Find \(\overrightarrow{AB}\) for \(A(2,-1)\) and \(B(7,5)\).
- Multiply: \(-2\langle 3, -4 \rangle\).
- A person walks \(\langle 6,2 \rangle\) miles, then \(\langle -4,5 \rangle\). Find net displacement.
1.
\[
\sqrt{(-3)^2 + 4^2} = 5
\]
2.
\[
\langle 6, -5 \rangle
\]
3.
\[
\langle 7-2,\; 5-(-1) \rangle = \langle 5, 6 \rangle
\]
4.
\[
\langle -6, 8 \rangle
\]
5.
Net: \(\langle 2, 7 \rangle\)
Summary
- Vectors have magnitude and direction.
- Add components; scale components; magnitude uses the Pythagorean formula.
- Vectors model displacement, velocity, and physical forces.
- Draw a sketch for displacement problems.
- Use \(B - A\) for \(\overrightarrow{AB}\).
- Direction angle: check the quadrant.
- Magnitude is always nonnegative.