Percents
By the end of this lesson, you’ll be able to:
- Convert between percents, decimals, and fractions.
- Compute percent of a number, percent increase/decrease, percent change, and reverse percent.
- Solve word problems involving tax, discounts, interest, and mixtures.
Key Ideas
Percent means out of 100:
\[ 1\% = \frac{1}{100} = 0.01 \]
Conversions:
- percent → decimal: ÷100 (25% → 0.25)
- decimal → percent: ×100 (0.07 → 7%)
- percent → fraction: write over 100 and simplify (50% = 1/2)
- percent → decimal: ÷100 (25% → 0.25)
Percent increase and decrease use multiplicative factors:
Increase → multiply by \(1 + r\)
Decrease → multiply by \(1 - r\)
Common Problem Types
Percent of a Number
Example: What is 18% of 250?
\(0.18 \times 250 = 45\)
Percent Increase / Decrease
Example: A jacket costs $80 and is discounted 25%.
Discount = \(0.25 \times 80 = 20\)
Sale price = 80 − 20 = $60
Percent Change Formula
To find the percent a value increases/decreases relative to the original:
\[ \text{percent change} = \frac{\text{new} - \text{original}}{\text{original}} \times 100\% \]
Reverse Percent (Finding Original)
Example: After a 20% discount, the price is $64.
\(0.80x = 64 \Rightarrow x = 80\)
Consecutive Percent Changes
Multiply factors:
\[ (1.10)(0.90) = 0.99 \]
Net change = −1%.
Percents in Context
- Tax/tip → multiply by \(1+r\)
- Discounts → multiply by \(1-r\)
- Multi-step → apply each percent in order
Strategies
- Convert percents to decimals before multiplying.
- Use percent change formula anytime the phrase “by what percent” appears.
- Watch wording:
- “increase by 20%” vs “increase to 20%”.
- “increase by 20%” vs “increase to 20%”.
- For reverse percent problems, divide by the growth/decay factor.
Worked Examples
Example 1
Question: What is 12% of 450?
Solution: \(0.12 \times 450 = 54\)
Example 2
Question: A score rises from 40 to 50. What is the percent increase?
Change = \(10\)
Percent increase:
\[ \frac{10}{40} = 0.25 = 25\% \]
Example 3
Question: A laptop marked $1200 has a 15% discount and then 8% tax.
Discount: \(1200 \times 0.85 = 1020\)
Tax: \(1020 \times 1.08 = 1101.60\)
- Using additive thinking for percent increase/decrease instead of factors (e.g., adding 20 instead of multiplying by \(1.20\)).
- Computing percent change with the wrong denominator (should be the original value).
- Reversing percent problems incorrectly (e.g., dividing by 0.20 instead of 0.80 for a 20% discount).
- Assuming consecutive percent changes add (e.g., +20% then −20% = 0 — this is false).
- Mixing up “increase by 20%” vs “increase to 20%.”
Practice Problems
- What is 7.5% of 200?
- A coat is reduced 30% and sells for $140. What was the original price?
- A price rises 12% then 5%. Approximate the net percent change.
1.
\(7.5\% = 0.075\)
\(0.075 \times 200 = 15\)
Answer: 15
2.
30% discount → pay 70% of original.
\(0.70x = 140\)
\(x = 200\)
Answer: $200
3.
+12% → \(1.12\)
+5% → \(1.05\)
Product → \(1.12 \times 1.05 = 1.176\)
Net = \(17.6\%\) increase
Answer: +17.6%
Summary
- Percent = out of 100.
- Convert using ×100 / ÷100.
- Increase → multiply by \(1 + r\); decrease → multiply by \(1 - r\).
- Percent change uses
\[ \frac{\text{new - original}}{\text{original}} \times 100\%. \]
- Consecutive percents multiply (not add).
- Reverse percent uses division by the percent factor.
- Change percent to decimal immediately before multiplying.
- Percent change → always divide by the original value.
- For reverse percent problems, divide by \(1 \pm r\).
- Consecutive percent changes multiply — never add.